Question

The sum of the squares of three numbers is 138, while the sum of their productstaken two at a time is 131. their sum is:

Answer 1

Let the three numbers are a,b,c

a²+b²+c²=138

ab+bc+ca=131

so now

we know that

(a+b+c)²= a²+b²+c²+2( ab+bc+ca )

=138+2(131)

=138+262

=400

(a+b+c)=√(400)


(a+b+c)=20


Therefore,The sum of three numbers is 20

Answer 2

⛷Hi friend ,

Hope it helped