The sum of the two digit number and the number obtained by interchanging its digits is 99. Find the numbers
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let the numbers digit on ones place be x and that of tens place be y
so the number is 10y+x
according to the question
x+y=0
10x+y=99
so,
y=-x
10x-x=99
9x=99
x=11
then you=-11
so the number is 10y+x
then, 10×-11+11
-110+11
-99
please mark me as a brainliest
so the number is 10y+x
according to the question
x+y=0
10x+y=99
so,
y=-x
10x-x=99
9x=99
x=11
then you=-11
so the number is 10y+x
then, 10×-11+11
-110+11
-99
please mark me as a brainliest
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