the sum of three consecutive even natural number is 48.find the greatest of these numbers
Answers
Answered by
29
hey mate...
let the no. be n , n+2 , n+4.
so ATQ n+n+2+n+4=48
3n+6=48
3n=42
n=14.
so the largest number be 18.
let the no. be n , n+2 , n+4.
so ATQ n+n+2+n+4=48
3n+6=48
3n=42
n=14.
so the largest number be 18.
Answered by
14
Let, the smallest number be x, second x+2 and third x+4 then x+x+2+x+4=48 3x+6=48 3x=42 ,x=14 the greatest number =x+4=14+4=18
chenu101:
mark brainlist please
Similar questions