the sum of three consecutive even natural numbers is 78 find the greatest of these numbers
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Answered by
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let the numbers be x
x+1
x+2
now,
according to question
x+x+1+x+2=78
3x+3=78
3x=78-3
3x=75
x=75/3
x=25
1st number =x=25
2nd number =x+1=25+1=26
3rd number =x+2=25+2=27
greatest number is 27
x+1
x+2
now,
according to question
x+x+1+x+2=78
3x+3=78
3x=78-3
3x=75
x=75/3
x=25
1st number =x=25
2nd number =x+1=25+1=26
3rd number =x+2=25+2=27
greatest number is 27
GunjanJathliya:
wrong ans
Answered by
3
Here is your solution
Let ,
The first even number be x
The second even number be(x+2)
The third even number be (x+2)+2
Sum of three consecutive even numbers is 78
A/q
x + (x+2) + [(x+2)+2 = 78
x+x+x+2+2+2=78
3x + 6 = 78
3x = 78–6
3X= 72
X=24
The 3 consecutive number would be:-
The first even number => x = 24
The second even number =>(x+2) =24+2=26
The third even number=>(x+2)+2
=24+4=28
The largest amongst them is 28
Hope it helps you
Let ,
The first even number be x
The second even number be(x+2)
The third even number be (x+2)+2
Sum of three consecutive even numbers is 78
A/q
x + (x+2) + [(x+2)+2 = 78
x+x+x+2+2+2=78
3x + 6 = 78
3x = 78–6
3X= 72
X=24
The 3 consecutive number would be:-
The first even number => x = 24
The second even number =>(x+2) =24+2=26
The third even number=>(x+2)+2
=24+4=28
The largest amongst them is 28
Hope it helps you
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