the sum of three consecutive even numbers is 108. what is the smallest of the three numbers?
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☆ the sum of three consecutive even numbers is 108. what is the smallest of the three numbers
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Let the number be N.
Thn,
108 = N+(N+2)+(N+4) = 3N+6
3N=102
N= 34......✌✌
Answered by
3
here's another solution without using algebra
108/3=36, the mean of the numbers and also the middle number
36-2=34
36+2=38
34, 36, and 38 are the numbers
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