The sum of three consecutive even numbers is 66 .Find the numbers.
Answers
Answered by
3
Answer:
The numbers are 20, 22 and 24
Step-by-step explanation:
Let the smallest number be x
The other 2 numbers are (x + 2) and (x + 4)
Their sum is 66:
x + (x + 2) + (x + 4) = 66
x + x + 2 + x + 4 = 66
3x + 6 = 66
3x = 60
x = 20
Find the numbers:
smallest number = x = 20
2nd number = x + 2 = 20 + 2 = 22
3rd number = x + 4 = 20 + 4 = 24
Answer: The numbers are 20, 22 and 24
Answered by
0
Step-by-step explanation:
If the second number is n , then the first is n−2 and the third n+2 ,
so we have:66=(n−2)+n+(n+2)=3n
Dividing both ends by 3 ,we find n=22 .
So the three numbers are: 20,22,24 .
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