The sum of three consecutive integers is 13 more than the smallest integer.find the numver
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Answer:
first integer = 5
second integer =6
third integer = 7
Step-by-step explanation:
let first integer = x
second integer= x+1
third integer = x+2
according to statement ,
x+x+1+x+2 = x+13
3x+3 = x+13
3x-x = 13-3
2x = 10
⇒ x=5
∴first integer = x=5
second integer = x+1 = 5+1=6
third integer = x+2 = 5+2=7
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