the sum of three consecutive integers is 48. find the integers
Points are 20 so please with steps! No directly answer!
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let the no.s be x,(x+1),(x+2)
x+x+1+x+2=48
3x+3=48
3x=45
x=45/3
x=15
x+x+1+x+2=48
3x+3=48
3x=45
x=45/3
x=15
Roseokuchi:
there are three answer
Answered by
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HEY MY DEAR MATE UR ANS IS⤵
LET THE THREE CONSECUTIVE NUMBERS BE X , X+1 , X+2
THEIR SUM = 48
X + X+1 + X+2 = 48
3X + 3 = 48
3X = 48 - 3
3X = 45
X = 45/3
X = 15
The numbers are
X = 15
X+1 => 15 + 1 => 16
X+2 => 16 + 1 => 17
15,16,17 Are the three consecutive numbers that make sum 48
*HOPE IT HELPS U*❤❤✌
LET THE THREE CONSECUTIVE NUMBERS BE X , X+1 , X+2
THEIR SUM = 48
X + X+1 + X+2 = 48
3X + 3 = 48
3X = 48 - 3
3X = 45
X = 45/3
X = 15
The numbers are
X = 15
X+1 => 15 + 1 => 16
X+2 => 16 + 1 => 17
15,16,17 Are the three consecutive numbers that make sum 48
*HOPE IT HELPS U*❤❤✌
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