Question

The sum of three consecutive integers is 48 find three integers

Answer 1

let 1st integer be (a-d)
let 2nd integer be a
3rd be(a+d)
now,
a+a-d+a+d=48
3a=48
a=16

Answer 2

let the three integers be x-1 , x and x+1



given ,

sum of three digits = 48
so ,
3×x =48

so x = 16

first number x = 16

second number x+1= 17

and third number x-1= 15

so, the three consecutive numbers are 15,16and 17