Question

The sum of three consecutive integers is 53 more than the least of the integers, how do you find the integers?

Answer 1

Answer: The integers are 25,26,27

Step-by-step explanation:

If you assume, that the smallest number is x then the conditions in the task lead to equation:

x+x+1+x+2=53+x

3x+3=53+x

2x=50

x=25

So you get the numbers: 25,26,27

Answer 2

Let the smallest of the three integers be x.

So the others will be x+1, x+2 because all three of them are consecutive.

So, (x)+(x+1)+(x+2)= x+53. (Acc to the qstn)

2x=50

x=25.

Therefore the integers are 25,26 and 27.