Question

The sum of three consecutive multiples of 6 is 666 the second nymber is ​

Answer 1

Answer:

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Answer 2

Answer:

sum of three consecutive multiple of 6 is 666

6x,6(x+1),6(x+2)

Its given that

6x+6(x+1)+6(x+2)=666

6x+6x+6+6x+12=666

18x+18=666

18x=666-18

18x=648

x=648/18

x=36

so the numbers are

First number 36×6=216

Second number 36×6+6=222

Third number 36×6+12=228