The sum of three consecutive multiples of 7 is 357. find the smallest multiple
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a\q,. 7×x+7×(x+1)+7×(x+2)=357
7(x+x+1+x+2)=357
3x+3=357/7
3x+3= 51
3x=51-3
3x=48
x=48/3
x=16
™16 is the smallest multiple.
7(x+x+1+x+2)=357
3x+3=357/7
3x+3= 51
3x=51-3
3x=48
x=48/3
x=16
™16 is the smallest multiple.
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