the sum of three consecutive multiples of 7 is 777.find these multiples?
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7
Let three consecutive multiple of 7 be 7z , 7z+7 +7z+14
7z+7z+7+7z+14 = 777
21z+21 = 777
21z= 777-21
21z = 756
z=756/21=36
so the three consecutive no. are
7*36 =252
7*36+7 = 252+7 =259
7*36+14 = 252+14 =266
7z+7z+7+7z+14 = 777
21z+21 = 777
21z= 777-21
21z = 756
z=756/21=36
so the three consecutive no. are
7*36 =252
7*36+7 = 252+7 =259
7*36+14 = 252+14 =266
mahidhar1:
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Answered by
6
x+x+7+x+14 = 777
3x+7+14=777
3x+21=777
3x=777-21
3x=756
x=756/3
=252
1st no. = 252
2nd no. = 252+7 =259
3rd no. = 252 +14=266
3x+7+14=777
3x+21=777
3x=777-21
3x=756
x=756/3
=252
1st no. = 252
2nd no. = 252+7 =259
3rd no. = 252 +14=266
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