Question

the sum of three consecutive multiples of 7 is 777 find these multiples

Answer 1

Let the three consecutive multiples of 7 be 7x,7(x+1), and 7(x+2).

By given condition,

7x+7(x+1)+7(x+2)=777.
7x+7x+7+7x+14=777
21+21x=777 .....divide by 21
1+x=37
x=36

Now ,7x=7×36=252
7(x+1)=7×37=259
7(x+2)=7×38=266

Hence the three consecutive multiples of 7 are 252,259 and 266.

Answer 2

Here is your answer

Let,
The three consecutive multiples of 7 be 7x, 7x + 7 and 7x + 14.

7x + (7x + 7) + (7x + 14) = 777 (Given)

⇒21x + 21 = 777

⇒ 21x = 777 – 21

⇒ 21x = 756

⇒ x = 36


Number are:-

7x=7×36=252

7x + 7 = 252 + 7 = 259

7x + 14 = 252 + 14= 266


Hence,

The three consecutive multiples of 7 are 252, 259 and 266

Hope it helps you