Question

The sum of three consecutive multiples of 8 is 888. Find the multiples. ☺



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Answer 1

Answer:

8*35 ,8*37, 8*39 I think this is the answer

Answer 2

Let the first multiple of 8 be 8x.

The second consecutive multiple of 8 = 8( x + 1 )

The third consecutive multiple of 8 = 8( x + 2 )

It is given that the sum of these three consecutive multiples of 8 is 888

8x + 8 ( x + 1 ) +( 8x +2 ) = 888

8x + 8x + 8 + 8x + 16 = 888

8x + 8x + 8x + 8 + 16 = 888

24x + 24 = 888

24x = 888 - 24

24x = 864

x = 864

24

x = 36

First multiple 8x = 8 x 36

= 288

Second multiple 8(x + 8 )

= 8 x 36 + 8

= 296

Third multiple 8( x + 16 )

= 8 x 36 + 16

= 304