The sum of three consecutive natural numbers each divisible by 5, is 225. the largest among them is
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Since each number is divisible by 5 and are consecutive
So the numbers are x, x + 5 and x + 10
A/Q -->
x + x + 5 + x + 10 = 225
3x + 15 = 225
3x = 210
x = 70
So the numbers are
x = 70
x + 5 = 75
x + 10 = 80
The largest among them is 80
So, the required answer is 80.
Hope This Helps You!
So the numbers are x, x + 5 and x + 10
A/Q -->
x + x + 5 + x + 10 = 225
3x + 15 = 225
3x = 210
x = 70
So the numbers are
x = 70
x + 5 = 75
x + 10 = 80
The largest among them is 80
So, the required answer is 80.
Hope This Helps You!
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