The sum of three consecutive odd numbers is 69 find prime no. out of these
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let the first odd no. be 2n+1
second be 2n+3
third be 2n+5
Their sum = (2n+1) + (2n+3) + (2n+5) = 69
or, 6n+9 = 69
or, 6n = 69 - 9 = 60
so, n = 60/6 = 10
Hence the nos. are : 2(10)+1 , 2(10)+3 , 2(10)+5
i.e., 21, 23, 25
out of these clearly 23 is a prime no. which is only divisible by 1 and 23 only.
second be 2n+3
third be 2n+5
Their sum = (2n+1) + (2n+3) + (2n+5) = 69
or, 6n+9 = 69
or, 6n = 69 - 9 = 60
so, n = 60/6 = 10
Hence the nos. are : 2(10)+1 , 2(10)+3 , 2(10)+5
i.e., 21, 23, 25
out of these clearly 23 is a prime no. which is only divisible by 1 and 23 only.
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