The sum of three consecutive positive integers is 36. find the numbers
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Answer:
x + (x+1) + (x+2) = 36
x + x + 1 + x + 2 = 36
3x + 3 = 36
3x = 33
x = 11
first number = x = 11
second number = x+1 = 12
third number = x+2 = 13
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