The sum of three consecutive terms of an A. P. is 24 and their product is 224
. Find the terms.
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Let (a-d),a,(a+d) be the three terms of AP
sum of these three terms
a-d+a+a+d = 24
3a. = 24
a= 8
Sum of square of these terms :-
(a-d)²+a²+(a+d)²= 224
a²+d²-2ad+a²+a²+d²+2ad=224
3a²+2d²=224
d= ±4
Therefore terms are 12,8,4 or 4,8,12
sum of these three terms
a-d+a+a+d = 24
3a. = 24
a= 8
Sum of square of these terms :-
(a-d)²+a²+(a+d)²= 224
a²+d²-2ad+a²+a²+d²+2ad=224
3a²+2d²=224
d= ±4
Therefore terms are 12,8,4 or 4,8,12
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