Question

The sum of three number is 98. If the ratio of the first to the second is 2:3 and that of the second to the third is 5:8, find the three number

Answer 1

let the no.s be 2x and 3x in the first case and 5y and 8y in the second.


ATQ,
3x =5y
→x=5y/3-(i)
now,
2x+5y+8y=98 (from eq.i)
→ 2×5y/3+5y+8y=98
→10y/3+13y =98
→10y +39y=98×3
→49y=294
→y=6


Hence , the no. s are
5×6=30
8×6=48
10×6/3=60/3=20




hope this answer will clear your problem :-)

Answer 2

Answer:

Step-by-step explanation:

Solution:

Let the three numbers be x, y and z.

Sum of the numbers is 98.

x + y + z = 98………………(i)

The ratio of the first to the second is 2/3.

x/y = 2/3.

x = 2/3 × y.

x = 2y/3.

The ratio of the second to the third is 5/8.

y/z = 5/8.

z/y = 8/5.

z = 8/5 × y.

z = 8y/5.

Put the value of x = 2y/3 and z = 8y/5 in (i).

2y/3 + y + 8y/5 = 98

49y/15 = 98.

49y = 98 × 15.

49y = 1470.

y = 1470/49.

y = 30 .

Therefore, the second number is 30.

Answer: (c)