the sum of three numbers in A.P is 15 and the sum of their square is 93 find the numbers
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Answer:
9.5
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Solution:-
let the required number be ( a - d ) , a and ( a + d )
The sum of three number is 15
⇒ a - d + a + a + d =15
⇒ 3a = 15
⇒ a = 15/3
⇒a = 5
The product of three number is 93
⇒a . ( a - d ) . ( a + d ) = 93
⇒a ( a² - d² ) = 93
when a = 5
⇒ 5 ( 5² - d² ) = 93
⇒ 5 ( 25 - d² ) = 93
⇒ 125 - 5d² = 93
⇒ - 5d² = 93 - 125
⇒ - 5d² = - 32
⇒ 5d² = 32
⇒ d = ±√32/5
Thus a = 5 and d = ±√32/5
Hence required number ( 5 + √32/5 ) , 5 , ( 5 - √32/5 ) and ( 5 - √32/5 ) , 5 , ( 5 + √32/5 )
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