Question

The sum of three numbers in A.P. is 36 and their product is 1140,then one of the number is :

Answer 1

Answer:

i hope this helps you

Step-by-step explanation:

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Answer 2

Answer:

(5,12,19) these are the numbers which are in A.P

Step-by-step explanation:

Let the number be a-d, a a+d

According to the question,

The sum of the three numbers in A.P. is 36

so, a-d+a+a+d=36

3a=36

a=12

their product is 1140

so, (a-d)*a*(a+d)= 1140

= a* ($a^{2}$-$d^{2}$)=1140

Put the value of a=12 in the above equation, and we get,

=12(144-$d^{2}$)= 1140

=(144-$d^{2}$)= 95

=144-95= 49=$d^{2}$

d=7

now put the value of "a" and "d" to get the number value,

(a-d, a ,a+d)

(12-7, 12, 12+7)

(5,12,19) these are the numbers which are in A.P.

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