The sum of three numbers in an AP is 21 and its product is 315 find them
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Here,
(a-d)+a+(a+d)=21
a-d+a+a+d=21
3a=21
a=7
Also,
(a-d)*a*(a+d)=315
(a^2-d^2)a=315
Put the value of a,
49-d^2=315/7
-d^2=45-49
-d^2=-5
d^2=5
d=2.22(approx.)
First Term= a-d= 4.77(approx.)
Second Term= a =7
Third Term = a+d =9.22
(a-d)+a+(a+d)=21
a-d+a+a+d=21
3a=21
a=7
Also,
(a-d)*a*(a+d)=315
(a^2-d^2)a=315
Put the value of a,
49-d^2=315/7
-d^2=45-49
-d^2=-5
d^2=5
d=2.22(approx.)
First Term= a-d= 4.77(approx.)
Second Term= a =7
Third Term = a+d =9.22
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