Question

The sum of three numbers is 91. If the second
qumber is 4 times the first number and the
third number is twice the second number, find
the three numbers.​

Answer 1

The problem is solved below..

Answer 2

Answer:

$\large{\boxed{\sf\pink{Numbers = 7,\: 28,\: \& \: 56 }}}$

Solution:-

Let the 1st number be x

$\therefore$ 2nd number = 4x

$\therefore$ 3rd number = 2(4x) = 8x

${\underline{\bf\red{ATQ:-}}}$

$\Rightarrow\sf x + 4x + 8x = 91 \\\\\Rightarrow\sf 13x = 91 \\\\\Rightarrow\sf x =\cancel{\dfrac{91}{13}} \\\\\Rightarrow{\boxed{\sf\pink{x = 7}}}$

$\rule{100}{2}$

Numbers:-

$\rightarrow\sf First \: number (x)$ = $\large{\boxed{\sf\green{7}}}$

$\rightarrow\sf 2nd \: number(4x) = 4(7)$ = $\large{\boxed{\sf\red{28}}}$

$\rightarrow\sf 3rd \: number (8x) = 8(7)$ = $\large{\boxed{\sf\blue{56}}}$