Question

The sum of three numbers of AP is 3 and their product is -35. Find the numbers

Answer 1

Answer:

(a+d),(a),(a-d)

According to the question

a+d+a+a-d=3

a=1

now product

a{(a+d)(a-d)}=-35

1{(1-d^2}=-35

-d^2=-36

d =6

now an = a+(n-1)d

1+(n-1)6=-35

n-1=-6

n=-5

Answer 2

Answer:

a+d+a+a-d = 3

cancel +d and -d

a+a+a = 3

3a = 3

a = 1