The sum of two consecutive multiples of 2 is 18. Find the number.
Answers
Answered by
113
Let 2 consecutive multiples be ,x and (x+2)
x + (x+2) = 18
2x + 2 = 18
2x = 18 - 2
2x = 16
X= 16/2
X = 8
So the multiples are
X = 8
X+2 = 8+2 = 10
x + (x+2) = 18
2x + 2 = 18
2x = 18 - 2
2x = 16
X= 16/2
X = 8
So the multiples are
X = 8
X+2 = 8+2 = 10
Answered by
54
let the consecutive multiples of 2 be x and x+2
sum=18
x+x+2=18
2x+2=18
2x=16
x=8
therefore the consecutive multiples of 2 are 8 and 8+2=10
sum=18
x+x+2=18
2x+2=18
2x=16
x=8
therefore the consecutive multiples of 2 are 8 and 8+2=10
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