Question

The sum of two digit number and the
number obtained by reversing digit is and
the two digit is 21 and the two digit is differ 3 find the number​

Answer 1

Answer:

Let the two digit be x and y

∴ Number (2−digit) =10×x+y

Sum of 2−digit and reverse of it

⟹10x+y+10y+x=66 (given)

∴x+y=6 (equation 1)

Digits differ by 2

∴x−y=2 (equation 2)

On adding,

2x=8

⟹x=4

∴y=2

or, x+y=6 From 1 equation

and y−x=2 From 2 equation

On adding:

2y=8

y=4

x=2

∴ Two digit numbers are: 42 and 24

There are two such numbers.

Answer 2

Answer:

Step-by-step explanation:

Let the 2 digits be x,y. respectively

2 digit number =10x+y

2 digit number obtained by ususing the digit =10y+x

∴10x+y+10y+x=99

⇒11x+11y=99

⇒x+y=9

x−y=3

On adding : 2x=12

                    x=6

putting x in ⟶(i)

6+y=9

y=3

∴ Number =10x+y=63

or , 10y+x=36.