Question

the sum of two digit of a two digit number is 14 if we add 36 to the number the number get reversed find the original number​

Answer 1

Answer:

let ten's digit be 'x'

unit's digit + ten's digit = 14

unit's digit = 14-x

The number is 10x + (14-x)

as per the question: 10x + (14-x) +36 = 10(14-x) + x

10x-x = 140-10x-14+x-36

9x = -9x+140-50

9x+9x= 90

18x = 90

x=

$\frac{90}{18} = 5$

The required No: 10x+14-x = 10(5)+14-5

= 50+9=59