The sum of two number is 405 and their issue is 8 is to 7 find the number
Answers
Answered by
1
:p :p :p :p :p :p :p :p :p :p :p :p :p :p :p
Heya User,
--> I presume that the word there is "ratio" =_=
--> Now, suppose the no.s are x, y :->
Then,
--> x / y = 8 / 7
=> x / ( x + y ) = 8 / ( 8 + 7 )
=> x / 405 = 8 / 15 ----> [ x + y = 405 Given =_= ]
=> x / 27 = 8
=> x = 27 * 8 = 216 || y = 405 - x = 405 - 216 = 189
Eh! There we are done =_= ... No.s are 216 and 189...
Heya User,
--> I presume that the word there is "ratio" =_=
--> Now, suppose the no.s are x, y :->
Then,
--> x / y = 8 / 7
=> x / ( x + y ) = 8 / ( 8 + 7 )
=> x / 405 = 8 / 15 ----> [ x + y = 405 Given =_= ]
=> x / 27 = 8
=> x = 27 * 8 = 216 || y = 405 - x = 405 - 216 = 189
Eh! There we are done =_= ... No.s are 216 and 189...
Answered by
0
let's us keep the 2 numbers be 8a:7a
then,acc to question
8a+7a=405
15a=405
a=405÷15
a=27
then, the first number is=8a=8×27=216
the second number is=7a=7×27=189
I hope it will hepl!!!
then,acc to question
8a+7a=405
15a=405
a=405÷15
a=27
then, the first number is=8a=8×27=216
the second number is=7a=7×27=189
I hope it will hepl!!!
Similar questions