Question

the sum of two number is 80 and the greater number exceeds twice the smaller by 11 find the numbers

Answer 1

Let first number be x.
So , other number = 2x+11
According to the question
x+2x+11=80
3x+11=80
3x=69
x = 23
First number = x = 23
Other number = 2x + 11 = 2*23 + 11 =46 +11 = 57

Answer 2

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Greater no. = x = 57

Smaller no. = 23

_______________________________________

The sum of two numbers is 80.

Thus,

• Let the greater number be "x" then smaller number will be "(80-x)"

Also,

• The greater number exceeds twice the smaller by 11.

Thus,

Greater no. = 2•(Smaller no.) + 11

⇒x = 2(80-x) + 11

⇒ x = 160 - 2x + 11

⇒x + 2x = 160 + 11

⇒3x = 171

⇒x = 171/3

⇒x = 57

Hence,

Greater no. = x = 57

Smaller no. = 80-x = 80-57 = 23