Question

The sum of two number is 99.if one exceed the other by 9,find the numbers

Answer 1

Let the two numbers be x and x+9
ATQ, x+x+9=99
=2x+9=99
=2x=99-9
=2x=90
=x=90/2
=x=45

Given that another number exceed by 9. So another number is x+9.And x=45
45+9=54.
Therefore, two numbers are 45 and 54.
Hope it help.........

Answer 2

Answer:

The no.s will be 45 and 54

Step-by-step explanation:

Let the smaller no. be = x

Let the bigger no. be = x + 9

So now, A/Q

= x + x + 9 = 99

= 2x = 99 - 9

= 2x = 90

= x = 90 ÷2 = 45

Therefore the no.s are

Smaller no. = x = 45

Bigger no. = x + 9 = 54