the sum of two number is 99.if one exceeds tge other by 9,find the number
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Answered by
102
Let the first no. be x
Then next no. is x+9
So, x+x+9= 99
» 2x+9 = 99
» 2x = 99-9 = 90
» x = 90/2= 45
so, one no. is 45 and other is 45+9 = 54.
Hope it helps....
Then next no. is x+9
So, x+x+9= 99
» 2x+9 = 99
» 2x = 99-9 = 90
» x = 90/2= 45
so, one no. is 45 and other is 45+9 = 54.
Hope it helps....
Answered by
38
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