Question

the sum of two number is74,one of the number is 10 more than the other number what are the number?

Answer 1

Let first number be x
So other number is x + 10
ATP
x + x + 10 = 74
2x + 10 = 74
2x = 74 - 10
2x = 64
x = 64/2
x = 32
First number is 32
Second number is x + 10 = 32 + 10 = 42

Answer 2

$x + x + 10 = 74$
$2x + 10 = 74$
$2x = 74 - 10$
$2x = 64$
$x =64 \div 2$
$x = 32$
$(1) = > x = 32$
$(2) = > x + 10 = 32 + 10 = 42$