Question

the sum of two numbers are 18 if one of them is 7 whole 3/7 find the other​

Answer 1

Answer:

7whole 3/7 = 52/7

now,

x+y =18

let x = 52/7

52/7 + y = 18

y = 18 - 52/7

y= 74/7

y= 1 whole 4/7

Answer 2

Given :–

• Sum of two numbers = 18.
• One number = $7\dfrac{3}{7}$

To Find :–

• The other number.

Solution :–

Let,

The other number be x.

According to the question,

One number + Other number = Sum of two numbers.

• One number = $7\dfrac{3}{7}$
• Sum of two numbers = 18.

So,

→ $7 \dfrac{3}{7} + x = 16$

First, we need to covert mixed fraction to simple fraction.

For converting, first we multiply the front side number (7) by the denominator (7), then we get the result of the multiplication, we add the numerator from the result of the multiplication.

So,

→ $\dfrac{3 + 49}{7} + x = 16$

→ $\dfrac{52}{7} + x = 16$

→ $x = 16 - \dfrac{52}{7}$

→ $x = \dfrac{16}{1} - \dfrac{52}{7}$

→ $x = \dfrac{112 - 52}{7}$

→ $x = \dfrac{60}{7}$

OR,

→ $x = 8\dfrac{4}{7}$

Hence,

The other fraction is $x = 8\dfrac{4}{7}$

Check :–

First number + Other number = Sum of two numbers.

Here the values are,

• First number = $7\dfrac{3}{7}$
• Other number = $8\dfrac{4}{7}$
• Sum of two numbers = 16.

Now, put all the values.

If the addition of both numbers is 16, then the answer is correct.

Now, solve this.

→ $7\dfrac{3}{7}$ + $8\dfrac{4}{7}$

Convert it to mixed fraction into fraction.

→ $\dfrac{52}{7}$ + $\dfrac{60}{7}$

→ $\dfrac{52 + 60}{7}$

→ $\dfrac{\cancel{112}}{\cancel7}$

→ 16

Since, we get 16 as the result of sum of the both numbers.

So, the other number $8\dfrac{4}{7}$ is correct.