The sum of two numbers is 15 and the difference of their squares is 15. The difference of the numbers is :(A) 0 (B) 1(C) 4 (D) 6
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so option B is right. hope you have your answer
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ranju99:
hi
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Let the numbers be x n y.
FIRST CONDITION :
x+y= 15___________(i)
SECOND CONDITION :
x²-y²= 15_____(ii)
Solving second eq:
x²-y²=(x+y)(x-y)
(Placing value of x+y frm eq (i))
15=15(x-y)
Therefore,
x-y=15/15=1
ANSWER: (B) =1.
____HOPE IT HELPS____
FIRST CONDITION :
x+y= 15___________(i)
SECOND CONDITION :
x²-y²= 15_____(ii)
Solving second eq:
x²-y²=(x+y)(x-y)
(Placing value of x+y frm eq (i))
15=15(x-y)
Therefore,
x-y=15/15=1
ANSWER: (B) =1.
____HOPE IT HELPS____
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