The sum of two numbers is 20 and their product is 40. the sum of their reciprocals is
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let 1st no. be x
2nd no. will be 20-x
1st case
x*(20-x)
20x-x^2=40
x^2-20x=40
x^2-20x-40
a=1
b=-20
c=-40
b^2-4ac=400+160=560
x=-b+_(b^2-4ac)/2a= 20+_560/2
(+)
x=580/2=290
(-)
x=-540/2
=-270
let x=290
another number =20-290=-270
atq
1/290+1/270=27+29/7830=56/7830
2nd no. will be 20-x
1st case
x*(20-x)
20x-x^2=40
x^2-20x=40
x^2-20x-40
a=1
b=-20
c=-40
b^2-4ac=400+160=560
x=-b+_(b^2-4ac)/2a= 20+_560/2
(+)
x=580/2=290
(-)
x=-540/2
=-270
let x=290
another number =20-290=-270
atq
1/290+1/270=27+29/7830=56/7830
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