Question

The sum of two numbers is 64, and the second number is 16 less than the first. What are numbers ?​

Answer 1

Step-by-step explanation:

let the numbers be x&y

x+y=64

y= x-16

= x+x-16=64

=2x-16=64

=2x=64+16

=2x=80

x=40

40+y=64

y=64-40

y=24

Answer 2

$\huge{\underline{\underline{\huge{\bold{Question \: :-}}}}}$

★ The sum of two numbers is 64 , and second number is 16 less than the first . Find the numbers.

$\huge{\underline{\underline{\huge{\bold{Answer \: :-}}}}}$

➙ The first number is 40 & second number is 24.

$\huge{\underline{\underline{\huge{\bold{Solution \: :-}}}}}$

Given :-

• The sum of two numbers is 64 .
• The second number is 16 less than the first.

To Find :-

• The two number being added .

Solution :-

• Let first number be ' x '

So , The Second number is x - 16

According to the question , The sum of two numbers is 64 .

x + ( x - 16 ) = 64

➝ x + x = 64 + 16

➝ x + x = 80

➝ 2 x = 80

➝ x = $\cancel{\dfrac{80}{2}}$

➝ x = 40

The first number is 40 .

The Second number is x - 16 =

➝ 40 - 16 = 24

So, The Second number is 24 .

$\huge{\underline{\underline{\huge{\bold{Verification \: :-}}}}}$

The sum of two numbers is 64

➝ x + x - 16 = 64

➝ 40 + 24 = 64

➝64 = 64

➠ Hence, Verified .