the sum of two numbers is 7 and 2 times the first exceed thrice the second number find the number
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Answered by
1
Answer:
Step-by-step explanation:
⇒2x+3y=92 -------> {1}
⇒4x−7y=2 ------> {2}
multiply the first equation by 2 , and subtract equation (1) from equation (2)
4x+6y=184
−(4x−7y=2) , we get
⇒13y=182
⇒y= 183/13 = 14
Put y=14 in (1)
2x+3y=92
⇒2x+3×14=92
⇒2x=92−42=50
∴x= 50/2 = 25
∴x=25 and y=14
Answered by
1
Answer:
The first answer is right
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