the sum of two numbers is 85, if one number exceeds the other by 7 find the number
Answers
Answered by
66
let one no. be x
then the other no. is (x+7)
so x +x+7=85
so 2x+7=85
2x=85-7
2x=78
x=78/2
x=39
now, x=39
x+7=39+7 =46
then the other no. is (x+7)
so x +x+7=85
so 2x+7=85
2x=85-7
2x=78
x=78/2
x=39
now, x=39
x+7=39+7 =46
Answered by
10
hi friend. let one no. be x and other no. be y. then one equations is x +y = 85 and another equations is x -y=7 .then by elimation method
x + y = 85.......(1)
x - y =7..........(2)
(-) (+)=(-)
2y=92
y=92/2
y=46
x+y=85
we got the value of y, then
x+46=85
x=85-46
x=31
x + y = 85.......(1)
x - y =7..........(2)
(-) (+)=(-)
2y=92
y=92/2
y=46
x+y=85
we got the value of y, then
x+46=85
x=85-46
x=31
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