Question

The sum of zeroes of polynomial x^3-8x^2-x+6 is?

Answer 1

Given that,

$find \: sum \: of \: zeroes \: of \: the \: polynomial \: {x}^{3} - 8 {x}^{2} - x + 6 = 0$

Let,

• a = 1
• b = -8
• c = -1
• d = 6

➡ α + ß + γ = -b/a = -(-8)/1 = 8

➡ αß + ßγ + αγ = c/a = -1/1 = -1

➡ αßγ = -d/a = -6/1 = -6

Hence, it is solved...

Step-by-step explanation:

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