Question

the sum to infinity of the G.P 1/2,1/4,1/8,1/16 is ?

Answer 1

Answer:

sum S (n)=a/(1-r)

a is the 1st term = 1/2

r is the common difference =1/2(ratio of a term and its preceding ones)

so S (n)=(1/2)/(1-1/2)

=(1/2)/(1/2)=1

it is approximately equal to 1

we don't say exactly 1 because we don't know what is the value of infinity

so it is approximately equal to 1