Question

the surface energy of a liquid drop is u if it is spread into 1331 identical droplets surface energy of a small drop will be ​

Answer 1

Explanation:

Given The surface energy of a liquid drop is u if it is sprayed into 1331 identical droplets surface energy of a small drop will be  

• We know that Initial Surface energy = surface tension x Surface Area
•                                                             = σ x 4π R^2 where r is the radius of big drop.
• Now U = σ x 4πR^2
• Now final surface energy will be U f = σ x 4π x r^2 x 1331 (where r is radius of small drop and 1331 drops are formed.)
• We need to find a relation between r and R. So before spraying and after spraying we get
• 4/3 π R^3 = 1331 x 4/3 π r^3
• Now R^3 = 1331 r^3
• Or r = (R^3 / 1331)^1/3
• Or r = R / 11
• Now final surface energy will be σ x 4πr^2 x 1331
•                                            So σ x 4π (R / 11)^2 x 1331
•                                        = σ x 4πR^2 x 1331 / 121
• We know that σ x 4πR^2 = U
• So we get U x 11
• Or it will be 11 U

Reference link will be

https://brainly.in/question/6996848