Question

The taxi fare in a city is as follow:for the first 5km,the fare is RS 80 and for the subsequent distance it is RS 20per km.taking distance covered as Xkm and total fare as RS y , write a linear equation

Answer 1

ANSWER

____________

|x |0 |1 |2|

|y |3 |8 |13|

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Taxi fare for first kilometer = Rs. 8

Taxi fare for subsequent distance = Rs. 5

Total distance covered =x

Total fare =y

Since the fare for first kilometer = Rs.8

According to problem,

Fare for (x – 1) kilometer = 5(x−1)

So, the total fare y=5(x−1)+8

⇒y=5(x−1)+8

y = 5x – 5 + 8

⇒y=5x+3

Hence, y=5x+3 is the required linear equation.

Now the equation is

y=5x+3 ...(1)

Now, putting the value x=0 in (1)

y=5×0+3

y=0+3=3 So the solution is (0,3)

Putting the value x=1 in (1)

y=5×1+3

y=5+3=8. So the solution is (1,8)

Putting the value x=2 in (1)

y=5×2+3

y=10+3=13. So the solution is (2,13)