Question

The taxi fare in a city is as follows: For the first kilometer, the fare is Rs. 8 and for the subsequent distance it is Rs. 5 per km. Taking the distance covered as x km and total fare as Rs. y, writes a linear equation for this information

Answer 1

taking distance as x km
Rs y as total fare
the linear eqn is
5x+8=y
5x-y=-8
5x-y+8=0.
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Answer 2

⇒ Let the total fare be = y Rs

⇒ Distance covered be = x km

⇒ For first subsequent distance (x - 1) km fare = 5(x - 1)

⇒ y = 8 + 5 (x - 1)

⇒ y = 8 + 5x - 5

⇒ y = 5x + 3

⇒ The coordinates of the following linear equation

1) x = 0, y = 3 (0,3)

2) x = 1, y = 8 (1,8)

3) x = 2, y = 13 (2,13)

4) x = 3, y = 18 (3,18)