Question

the taxi fare in city is as follows : for the first kilometre,the fare is 8rupees and for the subsequent distance it is 5rupees per km .taking the distance covered as x km and total fare as rupees y , write linear equation for this information and draw graph .

Answer 1

According to question:-
y=(1×8)+(x-1)5
y=8+5x-5
y=5x+3

Now Make Its Solutions like this:-
When x=0 , y=3 etc.

Then Make Its Graph

Answer 2

⇒ Let the total fare be = y Rs

⇒ Distance covered be = x km

⇒ For first subsequent distance (x - 1) km fare = 5(x - 1)

⇒ y = 8 + 5 (x - 1)

⇒ y = 8 + 5x - 5

⇒ y = 5x + 3

⇒ The coordinates of the following linear equation

1) x = 0, y = 3 (0,3)

2) x = 1, y = 8 (1,8)

3) x = 2, y = 13 (2,13)

4) x = 3, y = 18 (3,18)

REFER THE ATTACHMENT FOR GRAPH