the temperature at which 500cc of a gas X at temperature 293K occupies half it's original volume (pressure constant)
calculate
Answers
Answered by
85
P= CONSTANT.
V1=500
V2=250
T1=293 K
T2=?
APPLY CHARLE'S LAW
V1/T1=V2/T2
500/293=250/T2
146.5K=T2
hope this helps you!!
V1=500
V2=250
T1=293 K
T2=?
APPLY CHARLE'S LAW
V1/T1=V2/T2
500/293=250/T2
146.5K=T2
hope this helps you!!
Answered by
6
Explanation:
14.56K is the answer
hope it helps
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