Question

The temperature of an object is raised from -10°C
to 35 °C. the change in temperature on the Fahr-
enheit scale of temperature is
1) 45 °F 2) 35 °F 3) 81°F 4) 25 °F​

Answer 1

Given :

▪ Initial temp. = -10°C

▪ Final temp. = 35°C

To Find :

▪ The change in temp. on the fahrenheit scale.

Formula :

✒ If Tc and Tf are the temperatures of a body on celcius and fahrenheit, then,

$\bigstar\:\underline{\boxed{\bf{\pink{\dfrac{T_C-0}{100}=\dfrac{T_F-32}{212-32}}}}}\\ \\ \bigstar\:\underline{\boxed{\bf{\green{T_F=1.8T_C+32}}}}$

Calculation :

$\implies\sf\:(T_F)_1=1.8(T_C)_1+32\\ \\ \implies\sf\:(T_F)_1=1.8(-10)+32\\ \\ \implies\sf\:(T_F)_1 =-18+32\\ \\ \implies\bf\:\red{(T_F)_1=14\:F}\\ \\ \implies\sf\:(T_F)_2=1.8(T_C)_2+32\\ \\ \implies\sf\:(T_F)_2=1.8(35)+32\\ \\ \implies\sf\:(T_F)_2=63+32\\ \\ \implies\bf\:\blue{(T_F)_2=95\:F}\\ \\ \rightarrow\sf\:\Delta{T_F}=(T_F)_2-(T_F)_1\\ \\ \rightarrow\sf\:\Delta{T_F}=95-14\\ \\ \rightarrow\underline{\boxed{\bf{\purple{\Delta{T_F}=81\:F}}}}$

Answer 2

Given:-

• Initial temp. = -10°C
• Final temp. = 30°C

To find:-

• change in temperature on the Fahrenheit scale

Formula:-

$\large\bold{\underline{\underline{\boxed{\sf{\red{ \dfrac{ \sf T_C - 0}{100} = \dfrac{ \sf T_F - 32}{212 - 32}}}}}}}$

And,

$\large\bold{\underline{\underline{\boxed{\sf{\blue{ \sf T_F = 1.8 T_C + 32}}}}}}$

This formula is used when $\sf T_C$ and $\sf T_F$ are temperatures of a body on celcius and Fahrenheit.

Solution:-

$\implies\sf{ \sf ( \sf T_F )_1 = 1.8 \sf ( \sf T_C )_1 + 32}$

$\implies \sf{ \sf ( \sf T_F )_1 = 1.8( - 10) + 32}$

$\implies \sf{ \sf ( \sf T_F )_1 = -18 + 32}$

$\implies \bold{\underline{\underline{\boxed{\sf{\green{ \sf ( \sf T_F )_1 = 14F}}}}}}$

$\implies \sf{ \sf ( \sf T_F )_2 = 1.8 \sf ( \sf T_C )_2 + 32}$

$\implies \sf{ \sf ( \sf T_F )_2 = 1.8(35)}$

$\implies \sf{ \sf ( \sf T_F )_2 = 63 + 32}$

$\implies \bold{\underline{\underline{\boxed{\sf{\pink{ \sf ( \sf T_F )_2 = 95F}}}}}}$

$\bullet$ Now, We get value of $\sf{ \sf ( \sf T_F )_1 \; and \; \sf ( \sf T_F )_1 .}$

Therefore,

★ change in temperature on the Fahrenheit scale:-

$\implies \sf{ \Delta \sf T_F = \sf ( \sf T_F )_2 - \sf ( \sf T_F )_1 }$

$\implies \sf{ \Delta \sf T_F = 95 - 14}$

$\implies \large\bold{\underline{\underline{\boxed{\sf{\purple{ \Delta \sf T_F = 95 - 14}}}}}}$

$\rule{200}{2}$