Question

The threshold frequency V⁰ for a metal is 7.0 x 10¹⁴s. Calculate the kinetic energy of an electron emitted when radiation of frequency V=1.0x 10¹⁵s⁻ hits the metal​

Answer 1

Answer:

If frequency of radiation = 1.0 x 10¹⁵s⁻¹

Energy of radiation is equal to Planck's Constant(6.626 x 10⁻³⁴ m² kg / s) multiplied by frequency

Energy of radiation=6.626 x 10⁻¹⁹ J

An electron on the surface requires a certain amount of energy to free itself from the atom. That energy is (Threshold frequency x Planck's constant)

Energy to free electron=4.638 x 10⁻¹⁹ J

Kinetic Energy of electron= Energy of radiation - Energy to free electron

KE=1.988 x 10⁻¹⁹ J ≈ 2 x 10⁻¹⁹ J