Physics, asked by singhveera851, 1 year ago

The threshold wavelength for photoelectric emission in tungsten is 240nm. What wavelength of light must be used in order that the emitted photoelectrons have a kemax of 1.2
e.V.

Answers

Answered by gautham2727

1

Answer

For photoelectric emission to take place the wavelength of incident

light must be less than

threshold value which is 5200 A∘

wavelength of IR light = 7800 A∘

wavelength of UV light = 4000 A∘

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