Science, asked by sgurwinder292, 1 year ago

The time of arrival and departure of a train at three stations A, B and C and the distance of stations B and C from station A are given
station A
arrival depart

A 0 08;00 08;15
B 120 11;15 11;30
C 180 13;00 13;15
plot and interprut the time graph for the train assuming that its motion between any two stations is uniform. (pg no 106 NCERT text book) table 8.4
pls.

Answers

Answered by arshikhan8123
6

Answer-

The time graph for the train assuming that its motion between any two stations is uniform is given in the picture uploaded below.

Explanation-

A to B : distance = 120 - 0 = 120 Km.

             time = 11:15 - 8:15 = 3 hours

             Average speed = 120 / 3 = 40Km/h

B to C : distance = 180 - 120 = 60 Km

             time = 11:30 - 13:00 = 3/2 hours

             Average speed = 60/3/2 = 40 Km/h

The X-axis represents time and Y-axis represents distance.

At 8:15 distance = 0 km

At 11:15 distance = 120 km

At 13:15 distance = 180 km

Hence, the time graph for the train assuming that its motion between any two stations is uniform is given in the picture uploaded below.

#SPJ2

Attachments:
Answered by syed2020ashaels
1

D arrival depart

A 0 8:00 08:15

B 120 11:15 11:30

C 180 13:00 13:15

A to B:

The distance from A to B is 120-0 = 120 km.

The time taken is 8:15 to 11:15 = 3 hrs.

The average speed will be

 \frac{120}{3}  = 40

from B to C

The distance from B to C = 180-120=60km

The time taken is from 11:30 to 13:00 = 1:30 hrs , which is 3/2 hrs.

The average speed will be

 \frac{60}{ \frac{3}{2} }  =  \frac{60 \times 2}{3}

which is 40.

The x axis represents time and the y axis represents distance

At the time 8:15 the distance covered is 0km

At 11:15 the distance covered is 120 km

At 13:15 the distance covered is 180 km.

Hence, the time graph for the train assuming that it's motion between any two station is uniform.

# spj2

Attachments:
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