The time of arrival and departure of a train at three stations A, B and C and the distance of stations B and C from station A are given
station A
arrival depart
A 0 08;00 08;15
B 120 11;15 11;30
C 180 13;00 13;15
plot and interprut the time graph for the train assuming that its motion between any two stations is uniform. (pg no 106 NCERT text book) table 8.4
pls.
Answers
Answer-
The time graph for the train assuming that its motion between any two stations is uniform is given in the picture uploaded below.
Explanation-
A to B : distance = 120 - 0 = 120 Km.
time = 11:15 - 8:15 = 3 hours
Average speed = 120 / 3 = 40Km/h
B to C : distance = 180 - 120 = 60 Km
time = 11:30 - 13:00 = 3/2 hours
Average speed = 60/3/2 = 40 Km/h
The X-axis represents time and Y-axis represents distance.
At 8:15 distance = 0 km
At 11:15 distance = 120 km
At 13:15 distance = 180 km
Hence, the time graph for the train assuming that its motion between any two stations is uniform is given in the picture uploaded below.
#SPJ2
D arrival depart
A 0 8:00 08:15
B 120 11:15 11:30
C 180 13:00 13:15
A to B:
The distance from A to B is 120-0 = 120 km.
The time taken is 8:15 to 11:15 = 3 hrs.
The average speed will be
from B to C
The distance from B to C = 180-120=60km
The time taken is from 11:30 to 13:00 = 1:30 hrs , which is 3/2 hrs.
The average speed will be
which is 40.
The x axis represents time and the y axis represents distance
At the time 8:15 the distance covered is 0km
At 11:15 the distance covered is 120 km
At 13:15 the distance covered is 180 km.
Hence, the time graph for the train assuming that it's motion between any two station is uniform.
# spj2